3x^2+5xy^2+2y^4=0

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Solution for 3x^2+5xy^2+2y^4=0 equation: 


Simplifying
3x2 + 5xy2 + 2y4 = 0

Reorder the terms:
5xy2 + 3x2 + 2y4 = 0

Solving
5xy2 + 3x2 + 2y4 = 0

Solving for variable 'x'.

Factor a trinomial.
(3x + 2y2)(x + y2) = 0


Subproblem 1
Set the factor '(3x + 2y2)' equal to zero and attempt to solve:

Simplifying
3x + 2y2 = 0

Solving
3x + 2y2 = 0

Move all terms containing x to the left, all other terms to the right.

Add '-2y2' to each side of the equation.
3x + 2y2 + -2y2 = 0 + -2y2

Combine like terms: 2y2 + -2y2 = 0
3x + 0 = 0 + -2y2
3x = 0 + -2y2
Remove the zero:
3x = -2y2

Divide each side by '3'.
x = -0.6666666667y2

Simplifying
x = -0.6666666667y2

Subproblem 2
Set the factor '(x + y2)' equal to zero and attempt to solve:

Simplifying
x + y2 = 0

Solving
x + y2 = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1y2' to each side of the equation.
x + y2 + -1y2 = 0 + -1y2

Combine like terms: y2 + -1y2 = 0
x + 0 = 0 + -1y2
x = 0 + -1y2
Remove the zero:
x = -1y2

Simplifying
x = -1y2
Solution
x = {-0.6666666667y2, -1y2}

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